A brooch is made with silver wire in the form of a circle with diameter $35\text{ mm}$. The wire is also used in making $5$ diameters which divide the circle into $10$ equal sectors. Find the total length of the silver wire required.
Step-by-Step Solution
Key Concept: Perimeter $= \pi d = \dfrac{22}{7} \times 35 = 110\text{ mm}$. Length of 5 diameters $= 5 \times 35 = 175\text{ mm}$. Total wire $= 110 + 175 = 285\text{ mm}$.
Circumference $= \dfrac{22}{7} \times 35 = 110\text{ mm}$. [1.0 Mark]
Wire for 5 diameters $= 5 \times 35 = 175\text{ mm}$. Total wire $= 110 + 175 = 285\text{ mm}$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Calculating circumference $= 110\text{ mm}$: 1.0 Mark
Adding 5 diameters to get $285\text{ mm}$: 1.0 Mark
Correct Answer: