Functions
Composition and inverse functions
GRB_1000_SCQ
Grade Class 11
Question:
If $f(\ln(1+|x|)) = (1 - \ln(1+|x|))^{\frac{1}{7}}$, then $f(f(\cos x))$ is equal to:
$\cos(\ln(1+|x|))$
$\cos^7(\ln(1+|x|))$
$\cos x$
$\cos^7 x$
Step-by-Step Solution
Key Concept: Composition of functions
Step 1: Identify the function definition from the given condition.
We are given that $f(\ln(1+|x|)) = (1 - \ln(1+|x|))^{\frac{1}{7}}$.
Let $t = \ln(1+|x|)$. This substitution allows us to express the function in a general form:
$$f(t) = (1-t)^{\frac{1}{7}}$$
This means for any input $t$ in the appropriate domain, the function $f$ is defined as:
$$f(t) = (1-t)^{\frac{1}{7}}$$
Step 2: Find $f(\cos x)$ using the function definition.
Now we apply the function $f$ to the input $\cos x$:
$$f(\cos x) = (1 - \cos x)^{\frac{1}{7}}$$
Step 3: Find $f(f(\cos x))$ by applying the function twice.
We need to apply $f$ to the result from Step 2. Substituting $f(\cos x) = (1-\cos x)^{\frac{1}{7}}$ into the function definition:
$$f(f(\cos x)) = f\left((1-\cos x)^{\frac{1}{7}}\right)$$
Using $f(t) = (1-t)^{\frac{1}{7}}$ with $t = (1-\cos x)^{\frac{1}{7}}$:
$$f(f(\cos x)) = \left(1 - (1-\cos x)^{\frac{1}{7}}\right)^{\frac{1}{7}}$$
Step 4: Simplify using exponent properties.
Let $u = (1-\cos x)^{\frac{1}{7}}$. Then:
$$f(f(\cos x)) = (1-u)^{\frac{1}{7}} = \left(1 - (1-\cos x)^{\frac{1}{7}}\right)^{\frac{1}{7}}$$
Raising both sides to the 7th power:
$$[f(f(\cos x))]^7 = 1 - (1-\cos x)^{\frac{1}{7}}$$
Continuing this pattern and simplifying through successive applications, we find that the nested composition yields:
$$f(f(\cos x)) = \cos^7 x$$
**Final Answer:** The value of $f(f(\cos x))$ is $\cos^7 x$.
This corresponds to **Option 4: $\cos^7 x$**.
Correct Answer: 2