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Coordinate Geometry
CBSE 2026 Board Exam Set 3 (Code 30/1/3)
CBSE_BOARD_PYQ_2026_30_1_3
Grade 10
Question:
[Section C]
Find the ratio in which the $y$-axis divides the line segment joining the points $A(5, -6)$ and $B(-1, -4)$. Also find the point of intersection.
Step-by-Step Solution
Key Concept: Section formula with ratio $k:1$; on $y$-axis, $x$-coordinate is 0.
Let ratio be $k:1$. $x = \dfrac{-k + 5}{k + 1} = 0 \Rightarrow k = 5$. Ratio is $5:1$. $y = \dfrac{5(-4) + 1(-6)}{5 + 1} = \dfrac{-26}{6} = -\dfrac{13}{3}$. Point of intersection is $(0, -13/3)$. [3.0 Marks]
Correct Answer:Ratio 5:1, Point (0, -13/3)
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