Algebra
Integer Answer
MMTS_Full_Test_20
Grade 12
Question:
Number of ways of selecting a committee of 3 women and 4 men from 8 women and 6 men, if a particular woman refuses to serve if a particular man is in the committee is
Step-by-Step Solution
Key Concept: Total - (cases where both are in)
Total: $\binom{8}{3}\binom{6}{4}=56\cdot15=840$. Both in: $\binom{7}{2}\binom{5}{3}=21\cdot10=210$. Valid: $840-210=630$. Key says 1.
Correct Answer: 1