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Linear Programming
NCERT Class 12
CBSE
Grade 12

Question:

A dealer wishes to purchase a number of fans and sewing machines. He has only ₹5760 to invest and space for at most 20 items. A fan costs ₹360 and a sewing machine costs ₹240. He can sell a fan at a profit of ₹22 and a sewing machine at a profit of ₹18. Maximize profit.

Step-by-Step Solution

Constraints: $x+y \le 20, 3x+2y \le 48$. Intersection $(8,12)$. [1.5 Marks]
$Z(8,12) = 176 + 216 = 392 \Rightarrow$ Max profit $= ₹392$. [1.5 Marks]

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🎯 Official CBSE Marking Scheme:
Formulating constraints and corner points: 1.5 Marks
Evaluating maximum profit $= ₹392$: 1.5 Marks

Correct Answer:
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