Circles Question - None

Question

Let the equation of circle be $(x - 3)^2 + (y - 0)^2 + \lambda y = 0$. If it passes through the point $(1, -2)$, find the value of $\lambda$.

Accepted Answer

Step 1: Since the circle passes through point $(1, -2)$, substitute the coordinates into the equation.

Step 2: $(1 - 3)^2 + (-2 - 0)^2 + \lambda(-2) = 0$

Step 3: $4 + 4 - 2\lambda = 0$

Step 4: $8 = 2\lambda$

Step 5: $\lambda = 4$

∴ Answer is $\lambda = 4$.

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