Polynomials
NCERT Exemplar Ch 02
CBSE_NCERT_EXEMPLAR_CH02
Grade 10
Question:
The zeroes of the quadratic polynomial $x^2 - 2x - 8$ are:
$-2, 4$
$2, -4$
$2, 4$
$-2, -4$
Step-by-Step Solution
Key Concept: Factorise by splitting the middle term: $x^2 - 4x + 2x - 8 = 0$.
Stepwise Solution:
$x^2 - 4x + 2x - 8 = x(x - 4) + 2(x - 4) = (x - 4)(x + 2) = 0$. [0.5 Mark]
$x = 4$ or $x = -2$. Zeroes are $-2, 4$. [0.5 Mark]
Marking Scheme:
• Correct factorisation: 0.5 Mark
• Correct zeroes: 0.5 Mark
Correct Answer: $-2, 4$
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