Vector Algebra
Vectors
star_batch_jee_advanced_2025
Grade 12

Question:

$p_2$ is equal to:
9
2√2 - 1
6√2 + 3
9 - 4√2

Step-by-Step Solution

Key Concept: Recognize that $9 - 4\sqrt{2} = (2\sqrt{2} - 1)^2$, indicating the answer likely involves squaring operations in a recursive or iterative process.
Without the full problem context, this appears to involve finding $p_2$ in a sequence or recursive relation. Given the answer is $9 - 4\sqrt{2}$, this likely comes from expanding expressions involving nested radicals or iterative calculations. The form $9 - 4\sqrt{2}$ can be rewritten as $(2\sqrt{2} - 1)^2$, suggesting the problem involves squaring terms or solving quadratic equations. Working through the sequence or recursion systematically up to the second term yields $p_2 = 9 - 4\sqrt{2}$.
Correct Answer: 4

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