Permutations & Combinations
Words from MATHEMATICS with Constraint
nta_pyq_2023_apr
Grade 11
Question:
If words from MATHEMATICS with C and S not together $=(6!)k$, then $k$ is equal to
Step-by-Step Solution
Key Concept: MATHEMATICS: 11 letters with M$\times$2, A$\times$2, T$\times$2. Total arrangements $=\frac{11!}{2!2!2!}$. With C,S together: $\frac{10!}{2!2!2!}\times2!$. Subtract.
$k=5670$.
Correct Answer: 2