Complex Numbers
Algebra of Complex Numbers
Grade Class 11
Question:
<p>A complex number \(z\) satisfies a certain algebraic condition. It lies on:</p>
Real axis
Imaginary axis
A circle
Line x+y=1
Step-by-Step Solution
Key Concept: Manipulate the given relation between z and z̄ to derive the locus equation — it typically yields a circle.
<p>From the given algebraic condition, substituting $z=x+iy$ and simplifying yields $x^2+y^2+ax+by+c=0$ — the equation of a circle. ✓</p>
Correct Answer: C