Application of Derivatives Question - CBSE

Question

The side of an equilateral triangle is increasing at the rate of $2 ext{ cm/s}$. The rate of increase of its area when the side is $10 ext{ cm}$ is:
(a) $10\sqrt{3} ext{ cm}^2/ ext{s}$
(b) $20\sqrt{3} ext{ cm}^2/ ext{s}$
(c) $5\sqrt{3} ext{ cm}^2/ ext{s}$
(d) $15\sqrt{3} ext{ cm}^2/ ext{s}$

Accepted Answer

$\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{2}(10)(2) = 10\sqrt{3}$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Evaluating $dA/dt = 10\sqrt{3}$ cm$^2$/s: 1.0 Mark

Question:

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