<p>[IIT JEE 2011] 30. If three successive terms of a G.P. with common ratio r(r > 1) are the lengths of the sides of a</p>
Step-by-Step Solution
Key Concept: Notice the hidden common ratio first. Once the ratio is pinned down, the rest of the progression falls into place very quickly.
Notice that the real unlock is the common ratio. A clever move here is to write consecutive terms in powers of the ratio and then use the given condition to collapse the algebra. Now, we invoke the power of the G.P. identities for the nth term and the sum, simplify patiently, and verify that the final answer is \(4\).
Correct Answer: 4