3D Geometry
SD Between Lines with Parameter — Sum
nta_pyq_2023_apr
Grade 12
Question:
$S$ = set of $\lambda$ for which SD between $\frac{x-\lambda}{0}=\frac{y-3}{4}=\frac{z+6}{1}$ and $\frac{x+\lambda}{3}=\frac{y}{-4}=\frac{z-6}{0}$ is 13. Then $8|\sum_{\lambda\in S}\lambda|$ is equal to
Step-by-Step Solution
Key Concept: Use SD formula; set $=13$. Solve quadratic for $\lambda$.
$306$.
Correct Answer: 1