Introduction to Trigonometry
CH08 Question Bank
CBSE_CH08_QUESTION_BANK
Grade 10
Question:
If $3\tan A = 4$, find the value of $\dfrac{4\cos A - \sin A}{2\cos A + \sin A}$.
Step-by-Step Solution
Key Concept: Divide numerator and denominator by cos A to express the fraction entirely in terms of tan A, then substitute.
$\tan A=\dfrac43$. Dividing numerator and denominator of the given expression by $\cos A$: $\dfrac{4-\tan A}{2+\tan A}$. [1.0 Mark]
$=\dfrac{4-\frac43}{2+\frac43}=\dfrac{\frac{8}{3}}{\frac{10}{3}}$. [1.0 Mark]
$=\dfrac{8}{10}=\dfrac45$. [1.0 Mark]
Correct Answer:
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