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Triangles
RD Sharma
CBSE
Grade 10
Question:
If $\Delta ABC \sim \Delta PQR$, $AD$ and $PS$ are medians of $\Delta ABC$ and $\Delta PQR$ respectively, prove that $\dfrac{\text{Perimeter}(\Delta ABC)}{\text{Perimeter}(\Delta PQR)} = \dfrac{AD}{PS}$.
Step-by-Step Solution
Key Concept: Ratio of perimeters equals ratio of corresponding sides, which equals ratio of corresponding medians.
$\Delta ABC \sim \Delta PQR \Rightarrow \dfrac{AB}{PQ} = \dfrac{BC}{QR} = \dfrac{AC}{PR} = \dfrac{\text{Perim}(ABC)}{\text{Perim}(PQR)}$. (1) [1.0 Mark] Also $\Delta ABD \sim \Delta PQS$ (by SAS, as $AB/PQ = BD/QS$ and $\angle B = \angle Q$) $\Rightarrow \dfrac{AB}{PQ} = \dfrac{AD}{PS}$. (2) [1.0 Mark] From (1) and (2): $\dfrac{\text{Perimeter}(\Delta ABC)}{\text{Perimeter}(\Delta PQR)} = \dfrac{AD}{PS}$. Proved! [1.0 Mark]
--- 🎯 Official CBSE Marking Scheme: Proving perimeter ratio equals side ratio: 1.0 Mark Proving $\Delta ABD \sim \Delta PQS \Rightarrow AB/PQ = AD/PS$: 1.0 Mark Concluding proof: 1.0 Mark
Correct Answer:
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