Find the zeroes of $f(x) = x^2 - 2$, and verify the relation with coefficients.
Step-by-Step Solution
Key Concept: $x^2 - 2 = (x - \sqrt{2})(x + \sqrt{2}) = 0 \Rightarrow x = \pm \sqrt{2}$.
Zeroes are $\sqrt{2}$ and $-\sqrt{2}$. [1.0 Mark]
Sum $= \sqrt{2} - \sqrt{2} = 0 = -0/1 = -b/a$.
Product $= (\sqrt{2})(-\sqrt{2}) = -2 = -2/1 = c/a$. Verified! [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Finding zeroes $\pm \sqrt{2}$: 1.0 Mark
Verifying sum and product: 1.0 Mark
Correct Answer: