Probability
Hypergeometric Distribution Variance
nta_pyq_2025_apr
Grade 12

Question:

Three defective oranges are accidentally mixed with seven good ones and on looking at them, it is not possible to differentiate between them. Two oranges are drawn at random from the lot. If $x$ denotes the number of defective oranges, then the variance of $x$ is
28/75
18/25
26/75
14/25

Step-by-Step Solution

Key Concept: X follows a hypergeometric distribution. Build the distribution table for $X = 0, 1, 2$ using combinations, then compute $E(X)$ and $E(X^2)$ to find variance.
${}^{10}C_2 = 45$. $P(X=0) = \frac{21}{45}$, $P(X=1) = \frac{21}{45}$, $P(X=2) = \frac{3}{45}$. $E(X) = \frac{3}{5}$. $E(X^2) = \frac{0\cdot21 + 1\cdot21 + 4\cdot3}{45} = \frac{33}{45}$. Var$(X) = \frac{33}{45} - \frac{9}{25} = \frac{165 - 81}{225} = \frac{84}{225} = \frac{28}{75}$.
Correct Answer: 28/75

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