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Coordinate Geometry
Ellipse, Eccentricity
jee_main_2026_april_6_shift_2
Grade None

Question:

The eccentricity of the ellipse x²/25 + y²/9 = 1 is:
A. 2/5
B. 3/5
C. 4/5
D. 5/3

Step-by-Step Solution

Key Concept: Ellipse eccentricity: e = √(1 - b²/a²).
Step 1: a² = 25, b² = 9. Step 2: e = √(1 - 9/25) = √(16/25) = 4/5.
Correct Answer: C
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