Permutations & Combinations
Counting
Grade None

Question:

<p>The total number not more than 20 digits that are formed by using the digits 0, 1, 2, 3, and 4 is</p>
<p>(1) \(5^{20}\)</p>
<p>(2) \(5^{20} - 1\)</p>
<p>(3) \(5^{20} - 1\)</p>
<p>(4) none of these</p>

Step-by-Step Solution

Key Concept: Numbers formed using digits {0,1,2,3,4} must have at most 20 digits where the first digit cannot be 0. Sum the count for all valid lengths: 1-digit through 20-digit numbers, accounting for the leading zero restriction.
<p><strong>Step 1:</strong> Identify valid numbers: 1-digit to 20-digit numbers using digits {0,1,2,3,4}.</p><p><strong>Step 2:</strong> For each length n (1 ≤ n ≤ 20):</p><ul><li>First digit: 4 choices {1,2,3,4} (cannot be 0)</li><li>Remaining (n-1) digits: 5 choices each {0,1,2,3,4}</li><li>Count for length n = 4 × 5^(n-1)</li></ul><p><strong>Step 3:</strong> Total = Σ(n=1 to 20) 4 × 5^(n-1) = 4[5^0 + 5^1 + 5^2 + ... + 5^19]</p><p><strong>Step 4:</strong> Using geometric series formula: = 4 × (5^20 - 1)/(5 - 1) = (5^20 - 1)</p><p>∴ Answer: B</p>
Correct Answer: B

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