Question:

The equation of the circle which passes through origin and cuts off intercepts $a$ and $b$ from axes is

$x^2+y^2+ax+by=0$

$x^2+y^2-ax-by=0$

$x^2+y^2+ax-by=0$

$x^2+y^2-ax+by=0$

Step-by-Step Solution

Key Concept: Circle through $(0,0)$, $(a,0)$, $(0,b)$: use general form $x^2+y^2+Dx+Ey+F=0$

$x^2+y^2-ax-by=0$.

Correct Answer: 2