Question:
The equation of the common tangents of the parabola \( y^2 = 4x \) and an ellipse \( \frac{x^2}{4} + \frac{y^2}{3} = 1 \) are -
(A) x - 2y + 4 = 0
(B) x + 2y + 4 = 0
(C) 2x - y + 1 = 0
(D) 2x + y + 1 = 0
Step-by-Step Solution
Key Concept: General
For hyperbola e = 2, so a = \frac{ae}{e} = \frac{4}{2} = 2, b = 2/\sqrt{4-1} = 2\sqrt{3}
Correct Answer: A