Polynomials
RD Sharma
CBSE
Grade 10
Question:
If $\alpha, \beta$ are the zeroes of $x^2 - 5x + 6$, find the value of $\alpha^2 - \beta^2$.
Step-by-Step Solution
Key Concept: $x^2 - 5x + 6 = (x - 2)(x - 3) = 0 \Rightarrow$ zeroes are $2$ and $3$. $\alpha^2 - \beta^2 = 3^2 - 2^2 = 5$ or $-5$.
Zeroes are $3$ and $2$. [1.0 Mark]
$\alpha^2 - \beta^2 = 3^2 - 2^2 = 9 - 4 = 5$ (or $-5$). [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Finding zeroes 2 and 3: 1.0 Mark
Evaluating $\pm 5$: 1.0 Mark
Correct Answer:
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