Matrices & Determinants
System of Linear Equations
Grade Class 12

Question:

For the system of linear equation<br>2x - y + 3z = 5<br>3x + 2y - z = 7<br>4x + 5y + &alpha;z = &beta;<br>Which of the following is(are) CORRECT?<br>(A) The system has infinitely many solutions for &alpha; = -5 and &beta; = 9<br>(B) The system has a unique solution for &alpha; &ne; -5 and &beta; = 8<br>(C) The system has infinitely many solutions for &alpha; = -6 and &beta; = 9<br>(D) The system is inconsistent for &alpha; = -5 and &beta; = 8
(A) The system has infinitely many solutions for &alpha; = -5 and &beta; = 9
(B) The system has a unique solution for &alpha; &ne; -5 and &beta; = 8
(C) The system has infinitely many solutions for &alpha; = -6 and &beta; = 9
(D) The system is inconsistent for &alpha; = -5 and &beta; = 8

Step-by-Step Solution

Key Concept: The system of linear equations has a unique solution if the determinant of the coefficient matrix is non-zero. If the determinant is zero, the system may have infinitely many solutions or be inconsistent depending on the consistency of the augmented matrix.
The coefficient matrix is A = [[2, -1, 3], [3, 2, -1], [4, 5, &alpha;]]. The determinant |A| = 2(2&alpha; + 5) + 1(3&alpha; + 4) + 3(15 - 8) = 4&alpha; + 10 + 3&alpha; + 4 + 21 = 7&alpha; + 35. For a unique solution, |A| &ne; 0, so 7&alpha; + 35 &ne; 0, which means &alpha; &ne; -5. If &alpha; = -5, |A| = 0. The augmented matrix is [[2, -1, 3, 5], [3, 2, -1, 7], [4, 5, -5, &beta;]]. Performing row operations: R2 -> 2R2 - 3R1 gives [0, 7, -11, -1], R3 -> R3 - 2R1 gives [0, 7, -11, &beta; - 10]. For the system to be consistent, the last two rows must be proportional, so &beta; - 10 = -1, which means &beta; = 9. If &beta; &ne; 9, the system is inconsistent. Thus, for &alpha; = -5 and &beta; = 8, the system is inconsistent.
Correct Answer: D

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