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Some Applications of Trigonometry
CH09 Question Bank
CBSE_CH09_QUESTION_BANK
Grade 10

Question:

An observer $1.5$ m tall is $28.5$ m away from a tower $30$ m high (measuring from the observer's eye level). Find the angle of elevation of the top of the tower from the observer's eye.

Step-by-Step Solution

Key Concept: First find the effective height of the tower above eye level, then apply tanθ = effective height/distance.
Effective height above eye level $=30-1.5=28.5$ m. [1.0 Mark]

$\tan\theta=\dfrac{28.5}{28.5}=1\Rightarrow\theta=45^\circ$. [1.0 Mark]

Correct Answer:
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