Algebra
Permutations & Combinations
MMTS_Full_Test_14
Grade 12

Question:

The number of ways to arrange letters of BANANA so that no two N's appear together is
40
48
60
36

Step-by-Step Solution

Key Concept: BANANA: B,A,A,A,N,N; arrange without NN adjacent
Total arrangements of BANANA: $6!/(3!2!)=60$. With NN together: treat as one unit: BAAAXN→ $5!/(3!)=20$. Without NN: $60-20=40$.
Correct Answer: 1

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