Real Numbers
RD Sharma
CBSE
Grade 10
Question:
If $\text{HCF}(a, b) = 12$ and $\text{LCM}(a, b) = 360$, and $a = 60$, then $b$ is:
(a) $72$
(b) $60$
(c) $84$
(d) $48$
Step-by-Step Solution
Key Concept: $b = \dfrac{12 \times 360}{60} = 72$.
$b = \dfrac{12 \times 360}{60} = 12 \times 6 = 72$. [1.0 Mark]
---
🎯 Official CBSE Marking Scheme:
Evaluating $b = 72$: 1.0 Mark
Correct Answer: $72$
Confused by the solution? Ask the AI to explain a specific step, tell you where you went wrong, or break down the key trap in this question.