Statistics
Corrected Mean and Variance
nta_pyq_2023_apr
Grade 11

Question:

Mean and variance of 12 observations are 9 and $\frac{4}{2}$ (note: variance=$\frac{4}{2}$). Two values 9 and 10 were wrongly noted instead of 7 and 14. If correct variance is $\frac{m}{n}$ with $\gcd(m,n)=1$, then $m+n$ is equal to
315
316
314
317

Step-by-Step Solution

Key Concept: Correct $\sum x_i$ by replacing 9+10 with 7+14 (same sum). Correct $\sum x_i^2$ by replacing $81+100$ with $49+196$. Recalculate variance.
Variance $=\frac{281}{36}$. $m+n=317$.
Correct Answer: 4

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