Statistics
Corrected Mean and Variance
nta_pyq_2023_apr
Grade 11
Question:
Mean and variance of 12 observations are 9 and $\frac{4}{2}$ (note: variance=$\frac{4}{2}$). Two values 9 and 10 were wrongly noted instead of 7 and 14. If correct variance is $\frac{m}{n}$ with $\gcd(m,n)=1$, then $m+n$ is equal to
Step-by-Step Solution
Key Concept: Correct $\sum x_i$ by replacing 9+10 with 7+14 (same sum). Correct $\sum x_i^2$ by replacing $81+100$ with $49+196$. Recalculate variance.
Variance $=\frac{281}{36}$. $m+n=317$.
Correct Answer: 4