Vector Algebra
Coplanar Non-Coplanar Conditions
Grade 12

Question:

<p>Let \(\hat{p},\hat{q},\hat{r}\) be three mutually orthogonal unit vectors. If vector \(\vec{s}\) satisfies \[\hat{p}\times(\vec{s}\times\hat{p})+\hat{q}\times(\vec{s}\times\hat{q})+\hat{r}\times(\vec{s}\times\hat{r})=\lambda\vec{s},\] find \(\lambda\).</p>

Step-by-Step Solution

Key Concept: Use the identity: u \times (v \times u) = |u|^2v - (u \cdot v)u (BAC–CAB). Sum over the three orthonormal vectors.
By BAC-CAB: $\hat{p}\times(\vec{s}\times\hat{p})=|\hat{p}|^2\vec{s}-(\hat{p}\cdot\vec{s})\hat{p}=\vec{s}-(\hat{p}\cdot\vec{s})\hat{p}$. Summing over $\hat{p},\hat{q},\hat{r}$: $\sum[\vec{s}-(\hat{e}\cdot\vec{s})\hat{e}]=3\vec{s}-\sum(\hat{e}\cdot\vec{s})\hat{e}=3\vec{s}-\vec{s}=2\vec{s}$. (The last step uses that $\{p,q,r\}$ is an orthonormal basis, so $\sum_e(\hat{e}\cdot\vec{s})\hat{e}=\vec{s}$ -- this is just resolving s into components.) Therefore $\lambda=\boxed{2}$.
Correct Answer: 2

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