Question:

The area (in sq. units) of the region described by $\{(x,y): y^2\leq2x\text{ and }y\geq4x-1\}$ is:

$\dfrac{11}{32}$

$\dfrac{8}{9}$

$\dfrac{11}{12}$

$\dfrac{9}{32}$

Step-by-Step Solution

Key Concept: Intersections of $y^2=2x$ and $y=4x-1$: $y=1,-1/2$. Integrate horizontally.

Area $=9/32$.

Correct Answer: 4