Binomial Theorem
Greatest Binomial Coefficient
Grade 11
Question:
<p>If \(a\), \(b\) and \(c\) are the greatest values of \(\binom{19}{p}\), \(\binom{20}{q}\) and \(\binom{21}{r}\) respectively, then</p>
<p>(A) \(\frac{a}{10} = \frac{b}{11} = \frac{c}{42}\)</p>
<p>(B) \(\frac{a}{11} = \frac{b}{22} = \frac{c}{21}\)</p>
<p>(C) \(\frac{a}{10} = \frac{b}{11} = \frac{c}{21}\)</p>
<p>(D) \(\frac{a}{11} = \frac{b}{22} = \frac{c}{42}\)</p>
Step-by-Step Solution
Key Concept: The greatest binomial coefficient in an expansion corresponds to the middle term(s). For odd n, there are two equal maximum coefficients; for even n, there is one.
<p><strong>Solution:</strong> The greatest binomial coefficient in $\binom{n}{r}$ occurs at the middle term.</p><p>For $n = 19$ (odd): $a = \max\binom{19}{p} = \binom{19}{9} = \binom{19}{10}$ — there are two equal maximum values</p><p>For $n = 20$ (even): $b = \max\binom{20}{q} = \binom{20}{10}$</p><p>For $n = 21$ (odd): $c = \max\binom{21}{r} = \binom{21}{10} = \binom{21}{11}$ — there are two equal maximum values</p><p>Then: $\frac{a}{\binom{19}{10}} = 1$, $\frac{b}{\binom{20}{10}} = 1$, $\frac{c}{\binom{21}{10}} = 1$</p><p>Computing the ratio: $\frac{\binom{19}{10}}{\binom{20}{10}} = \frac{11}{20}$ and $\frac{\binom{20}{10}}{\binom{21}{10}} = \frac{11}{21}$</p><p>This gives: $\frac{a}{11} = \frac{b}{22} = \frac{c}{42}$</p><p>∴ Answer is (D).</p>
Correct Answer: D