Definite Integration
Grade None

Question:

<p>If x(x<sup>4</sup> + 1)f(x) = 1, then&nbsp;<span class="math-tex">\(\int\limits_1^2 {f(x)} \)</span>dx equals</p>
<p style="display:inline"><span class="math-tex">\(\frac {1}{4}\)</span>log<span class="math-tex">\(\frac {32}{17}\)</span></p>
<p style="display:inline"><span class="math-tex">\(\frac {1}{8}\)</span>log<span class="math-tex">\(\frac {32}{17}\)</span></p>
<p style="display:inline"><span class="math-tex">\(\frac {1}{4}\)</span>log<span class="math-tex">\(\frac {16}{17}\)</span></p>
<p style="display:inline"><span class="math-tex">\(\frac {1}{2}\)</span>log<span class="math-tex">\(\frac {32}{17}\)</span></p>

Step-by-Step Solution

Key Concept: Multiply and divide the integrand by $x^3$ to create a derivative-friendly substitution of $t=x^4+1$, which simplifies the rational function into a standard partial fraction form.
<p>f(x) =&nbsp;<span class="math-tex">\(\frac {1}{x(x^4 + 1)}\)</span><br /> <span class="math-tex">\(\Rightarrow\)</span>&nbsp;<span class="math-tex">\(\int\limits_1^2 {f(x)} \)</span>dx =&nbsp;<span class="math-tex">\(\int\limits_1^2 {\frac{1}{{x({x^4} + 1)}}} \)</span>dx =&nbsp;<span class="math-tex">\(\int\limits_1^2 {\frac{{{x^3}}}{{{x^4}({x^4} + 1)}}} \)</span><br /> Let x<sup>4</sup> + 1 = t&nbsp;<span class="math-tex">\(\Rightarrow\)</span>&nbsp;x<sup>3</sup> dx =&nbsp;<span class="math-tex">\(\frac {1}{4}\)</span>dt<br /> <span class="math-tex">\(\Rightarrow\)</span>&nbsp;<span class="math-tex">\(\int\limits_1^2 {f(x)} \)</span>dx =&nbsp;<span class="math-tex">\(\frac{1}{4}\int\limits_2^{17} {\frac{1}{{(t - 1)t}}}\)</span>dt<br /> =&nbsp;<span class="math-tex">\(\frac{1}{4}\int\limits_2^{17} {\left( {\frac{1}{{t - 1)}} - \frac{1}{t}} \right)} \)</span>dt<br /> =&nbsp;<span class="math-tex">\(\frac{1}{4}\left[ {\log (t - 1) - \log t} \right]_2^{17}\)</span>&nbsp;-&nbsp;<span class="math-tex">\(\frac{1}{4}\left( {\log 1 - \log 2} \right)\)</span><br /> =&nbsp;<span class="math-tex">\(\frac{5}{4}\)</span>log 2 -&nbsp;<span class="math-tex">\(\frac{1}{4}\)</span>log 17<br /> =&nbsp;<span class="math-tex">\(\frac{1}{4}\)</span>log&nbsp;<span class="math-tex">\(\frac{32}{17}\)</span></p>
Correct Answer: A

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