Coordinate Geometry
Circles
MMTS_Full_Test_15
Grade 12
Question:
The equation of the circle which passes through $(1,0)$, $(0,1)$ and has smallest possible radius is
$x^2+y^2-x-y=0$
$x^2+y^2+x+y=0$
$x^2+y^2-2x-2y=0$
$x^2+y^2+2x+2y=0$
Step-by-Step Solution
Key Concept: Smallest circle through two points has diameter $= $ distance between points
Equation: $(x-1)(x-0)+(y-0)(y-1)=0\Rightarrow x^2+y^2-x-y=0$.
Correct Answer: 3