Permutations & Combinations
Grade None

Question:

<p>A committee of 12 is to be formed from 9 women and 8 men in which at least 5 women have to be included in a committee. Then the number of committees in which the women are in majority and men are in majority are respectively,</p>
<p style="display:inline">2016, 630</p>
<p style="display:inline">4134, 56</p>
<p style="display:inline">2352, 7329</p>
<p style="display:inline">2702, 1008</p>

Step-by-Step Solution

Key Concept: Solve by identifying all mutually exclusive combinations of men and women that satisfy the total committee size, the minimum gender constraint, and the specific majority condition.
<p><strong>Case I:</strong> Women are in majority<br /> The committee contains<br /> <span class="math-tex">\(\equiv\)</span>&nbsp;(7W &amp; 5M) or (8W &amp; 4M) or (9W &amp; 3M)<br /> <span class="math-tex">\(\Rightarrow\)</span>&nbsp;Number of committees that can be formed<br /> =&nbsp;<sup>9</sup>C<sub>7</sub>&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;<sup>8</sup>C<sub>5</sub>&nbsp;+&nbsp;<sup>9</sup>C<sub>8</sub>&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;<sup>8</sup>C<sub>4</sub>&nbsp;+&nbsp;<sup>9</sup>C<sub>9</sub>&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;<sup>8</sup>C<sub>3</sub><br /> = 36&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;56 + 9&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;70 + 1&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;56<br /> = 2016 + 630 + 56<br /> = 2702<br /> <strong>Case II:</strong>&nbsp;Men are in majority<br /> The committee contains 7M &amp; 5W<br /> <span class="math-tex">\(\Rightarrow\)</span>&nbsp;Number of committees that can be formed<br /> =&nbsp;<sup>8</sup>C<sub>7</sub>&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;<sup>9</sup>C<sub>5</sub><br /> = 8&nbsp;<span class="math-tex">\(\times\)</span>&nbsp;126 = 1008</p>
Correct Answer: D

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