Matrices & Determinants
Properties of determinants
Grade Class 12

Question:

The values of &alpha;, for which <br><table><tr><td>1</td><td>3/2</td><td>&alpha;+3/2</td></tr><tr><td>1</td><td>1/3</td><td>&alpha;+1/3</td></tr><tr><td>2&alpha;+3</td><td>3&alpha;+1</td><td>0</td></tr></table> = 0, lie in the interval
(-2,1)
(-3,0)
(-3/2, 3/2)
(0,3)

Step-by-Step Solution

Key Concept: Expand the determinant and solve the resulting quadratic equation in alpha.
Expanding the determinant: 1(0 - (3&alpha;+1)(&alpha;+1/3)) - 3/2(0 - (2&alpha;+3)(&alpha;+1/3)) + (&alpha;+3/2)((3&alpha;+1) - 2/3(2&alpha;+3)) = 0. Simplifying this leads to a quadratic equation in &alpha;. Solving it gives the roots which lie in the interval (-3, 0).
Correct Answer: 2

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