The locus of the point equidistant from the lines $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ and $\frac{x}{2} = \frac{y}{3} = \frac{z}{1}$ can be:
Step-by-Step Solution
Key Concept: The locus of points equidistant from two intersecting lines forms two planes whose normals are the angle bisectors between the lines.
The locus consists of the pair of planes that pass through the point of intersection of the two given lines and have their bisectors as normals. These bisecting planes contain the angular bisectors of the two lines at their intersection point.
Correct Answer: I need to find the locus of points equidistant from the two given lines.
**Line 1:** $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ with direction vector $\vec{d_1} = (1, 2, 3)$ passing through origin
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