The area of the region enclosed by the curves y = x - 4x + 4 and y 2 2 = 16 - 8x is :
Step-by-Step Solution
Key Concept: Apply the core result for area bounded by curves and simplify using the given constraints.
(1) 2 2 Area = \int (\sqrt16 - 8x - (x - 4x + 4)) dx 0 2 3/2 3 -(16 - 8x) x 2 = - + 2x + 4x] 12 3 0 8 = 3
Correct Answer: 1