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Introduction to Trigonometry
CH08 Question Bank
CBSE_CH08_QUESTION_BANK
Grade 10
Question:
In the given right triangle, find $\sin\theta$ and $\cos\theta$.
Step-by-Step Solution
Key Concept: Apply the ratio definitions directly using the given side lengths.
$\sin\theta=\dfrac{\text{opposite}}{\text{hypotenuse}}=\dfrac{8}{17}$. [1.0 Mark]
$\cos\theta=\dfrac{\text{adjacent}}{\text{hypotenuse}}=\dfrac{15}{17}$. [1.0 Mark]
$\cos\theta=\dfrac{\text{adjacent}}{\text{hypotenuse}}=\dfrac{15}{17}$. [1.0 Mark]
Correct Answer:
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