Find the HCF and LCM of $108, 120$ and $252$ by prime factorisation.
Step-by-Step Solution
Key Concept: $108 = 2^2 \times 3^3$, $120 = 2^3 \times 3 \times 5$, $252 = 2^2 \times 3^2 \times 7$.
$108 = 2^2 \times 3^3$, $120 = 2^3 \times 3 \times 5$, $252 = 2^2 \times 3^2 \times 7$. [1.0 Mark]
$\text{HCF} = 2^2 \times 3 = 12$.
$\text{LCM} = 2^3 \times 3^3 \times 5 \times 7 = 8 \times 27 \times 35 = 7560$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Prime factorisations: 1.0 Mark
HCF $= 12$, LCM $= 7560$: 1.0 Mark
Correct Answer: