Question:
<p>If A <span class="math-tex">\(\equiv\)</span> (3,1 + sin<span class="math-tex">\(\theta\)</span>) and B <span class="math-tex">\(\equiv\)</span> (-1, 1 + cos<span class="math-tex">\(\theta\)</span>), <span class="math-tex">\(\theta\)</span> <span class="math-tex">\(\in\)</span> R are two points and P is a point on the line x - y = 0 then minimum value of (PA + PB) is :</p>
<p style="display:inline">4</p>
<p style="display:inline">2</p>
<p style="display:inline">4 - <span class="math-tex">\(2 \sqrt{2}\)</span></p>
<p style="display:inline">4 + <span class="math-tex">\(2 \sqrt{2}\)</span></p>
Step-by-Step Solution
Key Concept: Since points A and B lie on opposite sides of the line x-y=0, the minimum value of PA+PB is simply the minimum distance AB calculated across all possible values of θ.
<p>4</p>
Correct Answer: A