<p>In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is</p>
Step-by-Step Solution
Key Concept: Use the relationship 2c = distance between foci and 2b = minor axis to find c and b, then apply e = c/a where a² = b² + c².
<p><strong>Step 1:</strong> Identify given information</p><p>Distance between foci = 6, so 2c = 6 → <strong>c = 3</strong></p><p>Minor axis = 8, so 2b = 8 → <strong>b = 4</strong></p><p><strong>Step 2:</strong> Find semi-major axis using a² = b² + c²</p><p>a² = 4² + 3² = 16 + 9 = 25</p><p><strong>a = 5</strong></p><p><strong>Step 3:</strong> Calculate eccentricity</p><p>e = c/a = 3/5 = <strong>0.6</strong></p><p>∴ Answer: A (e = 3/5 or 0.6)</p>
Correct Answer: A