Introduction to Trigonometry and Its Applications
NCERT Exemplar Ch 08
CBSE_NCERT_EXEMPLAR_CH08
Grade 10
Question:
If $\sin A = \dfrac{1}{2}$, then the value of $\cot A$ is:
$\sqrt{3}$
$\dfrac{1}{\sqrt{3}}$
$\dfrac{\sqrt{3}}{2}$
$1$
Step-by-Step Solution
Key Concept: If $\sin A = 1/2 \Rightarrow A = 30^\circ$. $\cot 30^\circ = \sqrt{3}$.
Stepwise Solution:
$\sin A = 1/2 \Rightarrow A = 30^\circ$. [0.5 Mark]
$\cot 30^\circ = \sqrt{3}$. [0.5 Mark]
Marking Scheme:
• Identifying angle $A = 30^\circ$: 0.5 Mark
• Evaluating $\cot 30^\circ = \sqrt{3}$: 0.5 Mark
Correct Answer: $\sqrt{3}$
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