Question:
<p>Let ABC be a right triangle with <span class="math-tex">\(\angle\)</span>BAC = 90<sup>o</sup> then <span class="math-tex">\(\left(\frac{r^{2}}{2 R^{2}}+\frac{r}{R}\right)\)</span> is equal to : (where r and R have usual meaning in triangle.)</p>
<p style="display:inline">cot B cot C</p>
<p style="display:inline">tan B tan C</p>
<p style="display:inline">sin B sin C</p>
<p style="display:inline">sec B sec C</p>
Step-by-Step Solution
Key Concept: Relate the ratio r/R to the triangle's angles using the identity r/R = cos A + cos B + cos C - 1 and simplify using the fact that B and C are complementary.
<p>sin B sin C</p>
Correct Answer: C