<p>If \(z = x - iy\) and \(z^{1/3} = p + iq\), then \(\dfrac{\left(\dfrac{x}{p} + \dfrac{y}{q}\right)}{(p^2 + q^2)}\) is equal to</p>
Step-by-Step Solution
Key Concept: If z^(1/3) = p + iq, then z = (p + iq)³. Expand this and equate real and imaginary parts with z = x - iy to find relationships between x, y, p, q. The expression simplifies using these relationships and properties of complex cube roots.
Step 1: Express $z$ in terms of $p$ and $q$.
Given $z^{1/3} = p + iq$, we cube both sides of the equation to find an expression for $z$.
$$z = (p + iq)^3$$
Step 2: Expand the cubic expression.
We expand the term $(p + iq)^3$ using the binomial expansion formula $(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$.
$$(p + iq)^3 = p^3 + 3p^2(iq) + 3p(iq)^2 + (iq)^3$$
$$ = p^3 + 3ip^2q + 3p(-q^2) + i^3q^3$$
Since $i^2 = -1$ and $i^3 = -i$, we substitute these values:
$$ = p^3 + 3ip^2q - 3pq^2 - iq^3$$
Step 3: Group the real and imaginary parts.
Combine the real terms and the imaginary terms from the expanded expression for $z$.
$$z = (p^3 - 3pq^2) + i(3p^2q - q^3)$$
Step 4: Equate real and imaginary parts to find $x$ and $y$.
We are given $z = x - iy$. Comparing this with the expression for $z$ from Step 3, we equate the real parts and the imaginary parts.
Equating the real parts:
$$x = p^3 - 3pq^2$$
Equating the imaginary parts:
$$-y = 3p^2q - q^3$$
From the second equation, we can find the expression for $y$:
$$y = -(3p^2q - q^3) = q^3 - 3p^2q$$
Step 5: Calculate the value of $\left(\dfrac{x}{p} + \dfrac{y}{q}\right)$.
Substitute the expressions for $x$ and $y$ obtained in Step 4 into the term $\left(\dfrac{x}{p} + \dfrac{y}{q}\right)$.
First, calculate $\dfrac{x}{p}$:
$$\frac{x}{p} = \frac{p^3 - 3pq^2}{p} = \frac{p(p^2 - 3q^2)}{p} = p^2 - 3q^2$$
Next, calculate $\dfrac{y}{q}$:
$$\frac{y}{q} = \frac{q^3 - 3p^2q}{q} = \frac{q(q^2 - 3p^2)}{q} = q^2 - 3p^2$$
Now, sum these two expressions:
$$\frac{x}{p} + \frac{y}{q} = (p^2 - 3q^2) + (q^2 - 3p^2)$$
$$ = p^2 - 3p^2 - 3q^2 + q^2$$
$$ = -2p^2 - 2q^2$$
Factor out $-2$:
$$ = -2(p^2 + q^2)$$
Step 6: Calculate the final expression.
Substitute the result from Step 5 into the given expression $\dfrac{\left(\dfrac{x}{p} + \dfrac{y}{q}\right)}{(p^2 + q^2)}$.
$$\dfrac{\left(\dfrac{x}{p} + \dfrac{y}{q}\right)}{(p^2 + q^2)} = \dfrac{-2(p^2 + q^2)}{(p^2 + q^2)}$$
Assuming $p^2 + q^2 \neq 0$, we can cancel the term $(p^2 + q^2)$ from the numerator and the denominator.
$$ = -2$$
Step 7: State the final answer.
The value of the given expression is $-2$.
This matches Option 2.
Correct Answer: C