Application of Derivatives
Tangents and Normals
JEE Main 2018
Grade 12

Question:

The equation of the tangent to the curve $y = x^2 + 4x + 1$ at the point where it crosses the $y$-axis is:
(1) $y = 4x + 1$
(2) $y = 4x - 1$
(3) $y = x + 1$
(4) $y = 4x$

Step-by-Step Solution

Key Concept: Find the point where the curve meets the $y$-axis (set $x = 0$), compute $f'(x)$ at that point, and then use the point-slope form of a line.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (1)

Master Application of Derivatives with Mathbee

Practice this topic under real exam conditions with strict timers, or ask our AI Mentor to explain the concepts step-by-step.

Start Practicing for Free