Application of Derivatives
Maxima and Minima
Premium Question
Grade 12
Question:
The minimum value of $f(x) = x^2 + \frac{16}{x^2}$ for $x > 0$ equals _____.
Step-by-Step Solution
Key Concept: Either differentiate $f$ and set $f'(x) = 0$, or rewrite $f(x)$ as a sum of two positive terms and apply the AM–GM inequality to bound it below.
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Correct Answer: 8