The number of rational terms in the expansion of $(2^{1/2} + 3^{1/5})^{10}$ is:
Step-by-Step Solution
Key Concept: Write the general term $T_{r+1} = \binom{10}{r} 2^{(10-r)/2} 3^{r/5}$, and determine for how many integer values of $r$ between 0 and 10 both $\frac{10 - r}{2}$ and $\frac{r}{5}$ are integers.
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Correct Answer: (2)