The middle term in the expansion of $(1 + x)^{10}$ is:
Step-by-Step Solution
Key Concept: Since the expansion of $(1+x)^{10}$ has 11 terms (an odd number), there is a single middle term — identify its position as $\left(\frac{10}{2} + 1\right)^{\text{th}}$ and write down $T_{r+1} = \binom{10}{r} x^r$ for that value of $r$.
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Correct Answer: (1)