The shortest distance between the circles $x^2 + y^2 = 1$ and $(x - 3)^2 + (y - 4)^2 = 4$ is _____.
Step-by-Step Solution
Key Concept: Centres $O_1 = (0, 0), O_2 = (3, 4)$; distance $d = 5$. Shortest gap between circles $= d - r_1 - r_2 = 5 - 1 - 2 = 2$.
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Correct Answer: 2