Definite Integration
Grade 12

Question:

<p>Evaluate \(\displaystyle\int_{-1}^1 xe^{|x|}\,dx\) [JEE Main 2022]</p>
0
2(e-1)
e-1
2e

Step-by-Step Solution

Key Concept: xe^|x| is an odd function (odd \times even = odd). Integral over symmetric interval [-1,1] = 0.
<div class='solution'> <p>Let $f(x)=xe^{|x|}$. Then $f(-x)=(-x)e^{|-x|}=-xe^{|x|}=-f(x)$: <strong>odd function</strong>.</p> <p>$$\int_{-1}^1 xe^{|x|}dx = \boxed{0}$$</p>
Correct Answer: A

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