Home > Definite Integration > JEE Main 2019 > DI-Q11
Definite Integration
Periodic Functions
JEE Main 2019
Grade 12

Question:

$\int_0^{2\pi} |\cos x| \, dx$ equals:
(1) $4$
(2) $2$
(3) $2\pi$
(4) $0$

Step-by-Step Solution

Key Concept: Use the periodicity and symmetry of $|\cos x|$ to reduce the integral over $[0, 2\pi]$ to four equal pieces, each over an interval of length $\pi/2$.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (1)

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